Table of Contents
- Lab - Components
- Lab - Setting up a Breadboard
- Doubt: How to make parallel circuits in a Breadboard
- Lab - Electronics & Using a Multimeter
- Lab - Switches
Lab - Components
The components lab was an extension of the material covered in the electricity notes but in more depth. This is a label I'll have to continue to revisit over over again as there's a lot of information and memorising this will take time.
I've modified my note-taking tool to support hover-style flashcards using the notes I'm taking as I work through the material.
There's a lof of informattion to grok and I'm hoping that spaced repetition and continuously quizzing myself will help familiarise me with these things much quicker.
Lab - Setting up a Breadboard
This explanation helped me understand how the breadboard is connected with each component.
The center row isolates both sides of the bread board which enables us to add in integrated circuit chips.
On the left there's a vertically connected series for the + and - electrical
Powering the breadboard.
I don't have a DC power supply I can use. Instead of that I am going to use the arduino to power my breadboard.
Looking up it's documentation I can see that I can provide power using the USB. The second pin on the left provides a
3.3v power supply and the second pin from the bottom is the ground (left). The 4th pin from the bottom is also ground (right).
Will it light?
Given the following circuit. Will the examples shown light up?
All components are connected correctly.
I can't tell from the image if the anode is connected to voltage, and cathode is connected to ground. If it is then the LED will light up.
Just from looking at this I can tell it won't work. Simply because the center vertical row disconnects the resistor's end which should be providing the voltage to the LED's anode.
This will light now that there's a connection provided between both sides using the small red wire.
It won't work. I know this because when I was experimenting with the arduino circuit for some reason having all the voltage and ground wires on the same connector did not light my LED.
Correct. But I don't know why.
So as per the description it says that both LED's connections are on the same junction row and therefore the LED is bypassed.
This makes sense to be based on the idea that the current will take the path of least resistance.
Since the metal wire connects all of those pieces. The current can easily flow through the ground wire directly instead of having to go through the LED.
I think this should work.
Doubt: How to make parallel circuits in a Breadboard
I see this example but it's not immediately clear to me how parallel circuits work especially with how current passes through various components.
I mean, I sorta get it. They're in a parallel line that are all connected. But this is something I'll need to keep in mind moving forward to pay more attention to.
Lab - Electronics & Using a Multimeter
- Touching Two Ends of a Wire: Beep
- Touching Two Points on a Switch: Beep
- Probing Points on a Breadboard: Beep (same row)
- Measuring Continuity Across Your Hand: Beep
- Measured voltage: 5v
Switched LED circuit
- Adding Up Voltage: There is a voltage drop when the push button is on. The voltage drop was around .5v
Components in Series LED Circuit
- Adding Up Voltage: The voltage for resistor is 0.88, for LEDs are 1.9 and 2.26 = 5.04. Total voltage is 5.08
Components in Parallel with Potentiometer
- Voltage increased from 1.74 to 2.55 as I increased the potentiometer.
Lab - Switches
Project 1: Three Switches in Parallel
Project 2: Three Switches in Series
Project 2: Three Switches in Series
Project 3: Switching a Motor
This I was unable to do successfully. The motor isn't running and I'm not sure about how to control the amperage.